In a quadrilateral A B C D angle d is equal to 150° and angle a = angle b=angle c
Eind angle A, angle b, and angle c

Step-by-step explanation:

Let ∠A = x

Therefore, ∠A = ∠B = ∠C = x

The sum of all angles of a quadrilateral is 360

∠D + ∠A + ∠B + ∠C =360

150 +x + x + x =360

150 + 3x = 360

3x = 360 - 150

3x = 210

x = 210/3

x = 70

∠A = ∠B = ∠C = x = 70°

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here is your answer

there are two angles that are alternate interior angle with angle 9

the angle 15 and angle 7 are alternate interior angle with angle 9.

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