Which set of angles has the same terminal arm as 70 degrees?

The set of angles that has the same terminal arm as 70 degrees is B = B ∈ {70° + n*360°, n ∈ Z}.

We have to determine, which set of angles has the same terminal arm as 70 degrees.

According to the question,

Let, The angle A and other angle B that have the same terminal arm as A can be written as,

B  = A + n × 360°

Where the value of angle A is 70 degrees.

B is the coterminal angle, and they have the same terminal,

And n is the number of integers.

Substitute the value of A in the equation,

B  = 70 + n × 360°

Two angles are coterminal if they are drawn in the standard position and both have their terminal sides in the same location.

Since the value of n is equal to 0 then A = B,

Therefore, The angles coterminal with itself is called trivial.

Hence, The set of angles that has the same terminal arm as 70 degrees is B = B ∈ {70° + n*360°, n ∈ Z}.

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B = B ∈ {70° + n*360° I n ∈ Z  } where Z is the set of the integer numbers.

Step-by-step explanation:

If we have an angle A, the other angles that have the same terminal arm than A can be written as:

B = A + n*360°

Here B is a "coterminal" angle to A. (they have the same terminal side)

where n can be any integer number (if n = 0 we have A = B, which is trivial, this means that any angle can be coterminal with itself.)

So we can write the set as:

B = B ∈ {70° + n*360° I n ∈ Z  }