Decide whether p(x)=x^3−5x^0.5+13x^2+8 is a polynomial function

y > 1/3x

y < = -x + 4

hope this : )

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

its the second choice.

step-by-step explanation:

the elements in the range will be 7 less than the elements in the domain.