The population of a city is increasing at a rate of 4% each year. In 2000, there were 236,000 people in the city. Write an exponential growth function to model this situation. Then find the population in 2009.

A = 236,000 (1+ 0.04)^9

335,902 people in 2009

Step-by-step explanation:

Hi, to answer this question we have to apply an exponential growth function:  

A = P (1 + r) t  

Where:  

p = original population (in 2000)

r = growing rate (decimal form) = 4/100 = 0.04

t= years  

A = population after t years  

Replacing with the values given:  

A = 236,000 (1+ 0.04) ^t

To find the population in 2009:

We have to calculate the number of years passed since 2000: (2009-2000 = 9 years =t)

Substituting t=9 in the function:

A = 236,000 (1+ 0.04)^9

A =335,902 people

Feel free to ask for more if needed or if you did not understand something.  

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!