Help needed.

7x^2+3y^2-4x

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Step-by-step explanation:

Ok, so let me show you how to do this.

First, distrubute the negative sign

12x^2-11y^2-13x-(5x^2-14y^2-9x)=

12x^2-11y^2-13x-5x^2+14y^2+9x

Now combine like terms

(12x^2-5x^2)=7x^2

(-11y^2+14y^2)=3y^2

(-13x+9x)=-4x

7x^2+3y^2-4x is the answer.

the answer will be

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.