An airplane is flying at an altitude of 40,000 feet. To avoid turbulence the pilot descends at a rate of 2,000 feet / minute for 3 minutes. He continues flying at this altitude until he decides the turbulence is over; then he ascends at a rate of 1,500 feet minute for 5.5 minutes. At what altitude is the plane now flying?

The plane is now flying at an altitude of 42,250 feet.

Step-by-step explanation:

Initially, he is at an altitude of 40,000 feet.

Descends at a rate of 2,000 feet / minute for 3 minutes.

So his altitude is now:

40,000 - 3*2,000 = 34,000

Ascends at a rate of 1,500 feet minute for 5.5 minutes.

The plane is now flying at an altitude of:

34,000 + 1,500*5.5 = 42,250

The plane is now flying at an altitude of 42,250 feet.

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.