Mathematics, 18.06.2020 23:57 reagan1514
Consider the curve given by the equation (2y+1)^3 β 24x = β3.
(a) Show that dy/dx = 4/(2y+1)^2.
(b) Write an equation for the line tangent to the curve at the point (β1,β2).
(c) Evaluate d2y/dx2 at the point (β1,β2).
(d) The point (16,0) is on the curve. Find the value of (yβ1)β²(0).
Answers: 1
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Consider the curve given by the equation (2y+1)^3 β 24x = β3.
(a) Show that dy/dx = 4/(2y+1)^2.
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