Find the probability that a randomly selected car from this sample had 222 doors or 444 doors. P\left(\text{2 doors OR 4 doors}\right)=P(2 doors OR 4 doors)=P, (, start text, 2, space, d, o, o, r, s, space, O, R, space, 4, space, d, o, o, r, s, end text, ), equals

Step-by-step explanation:

The question lacks appropriate diagram. Find the diagram attached below.

Probability is the likelihood or chance that an event will occur.

Probability  = expected outcome of event/total outcome of event

According to the set diagram;

the total number of cars that has 2 doors = 14+18 = 32

the total number of cars that has 4 doors = 20+25 = 45

Probability of randomly selecting a car that has 2 doors = 32/100

Probability of randomly selecting a car that has 4 doors = 45/100

Probability that a randomly selected car from this sample had 2 doors or 4 doors = P(2 or 4) = 32/100+45/100

= 77/100