The lengths of pregnancies are normally distributed with a mean of 208 days and a standard deviation of 15 days. A wife claimed to have given birth 308 days after a brief visit from her husband who was serving in the Navy. What is the probability of a pregnancy lasting 308 days or longer

0%

Step-by-step explanation:

We have the following information:

mean (m) = 208 days

standard deviation (s) = 15 days

We have that the z value would be:

z = (x - m) / sd

replacing we have:

z = (308 - 208) / 15

z = 6.66

However,

P (x> 308) = 1 - (x <308)

P (x> 308) = 1 - (z <6.66)

if we look for this value of z in the table we assume that it is 1, since the table reaches 3 and the value is 1. Therefore:

P (x> 308) = 1 - 1

P (x> 308) = 0

Which means that the probability is 0%, therefore it is a very unusual pregnancy.

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.