In triangle CDE the measure of angle E equals 90° the measure of angle C equals 81° De equals 51 feet find the length of cd to the nearest 10th of a foot

Step-by-step explanation:

Check the diagram of the triangle in the attachment below.

From the right angled triangle shown, CD is the hypotenuse and DE is the opposite side to ∠C. To get the length CD, we will use the SOH, CAH, TOA trigonometry identity.

According to SOH;

Sin∠C = opp/hyp = DE/CD

Given ∠C = 81° and DE = 51feet

Sin81° = 51/CD

CD = 51/Sin81°

CD = 51.63572feet

CD = 51.6 (to nearest tenth of a foot)

i think it is c, not positive though

step-by-step explanation:

answer: 48

just remember to use pemdas:

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