E. coli bacteria have a doubling time of 20 minutes. Starting with 30 E. coli bacteria, how many will there be 6 hours later? Group of answer choices 7,864,410 7,864,320 7,864,452 7,864,821

7,864,320

Step-by-step explanation:

Because the doubling time is 20 minutes, the bacteria would have gone through binary fission(cell division in bacteria) 18 times after 6hours(6*60/20)

Nt=N0 * 2^n

N0=starting population

n=number of times bacteria divide

So

30*2^18=7,864,320

you already gave the answer

step-by-step explanation:

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w