Which expression is a sum of cubes? -27a3b6+8a9b12
-9ab6 +9610
9ab6 + 8a12
27a3b8+8a9b12

The first possible answer, -27a³b^6 + 8a^9b^12, is the sum of cubes.

Step-by-step explanation:

The middle two possible answers involve " a " with no exponent, so these could not be correct.

Looking at the first and fourth possible answers, we see that the first term of -27a3b6+8a9b12 is a perfect cube; it could be re-written as (-3ab²)³.  The second term could be rewritten as (2a³b^4)³.  So the first possible ansswer is the SUM of CUBES.

b). 4320 have a nice day

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.