One angle of a triangle is obtuse. The sum of the measures of the other angles must be A. more than 90 degrees B. less than 90 degrees C. equal to 90 degrees help i need this 10 points please

B.less than 90 degrees

Step-by-step explanation:

Obtuse angle is greater than 90°

Since the sum of all 3 angles= 180°

The sum of other 2 angles less than  180°-90°= 90°

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)