Mathematics, 17.06.2020 20:57 kieran1982
The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y plus 7 equals negative StartFraction 2 over 5 EndFraction left-parenthesis x minus 10 right-parenthesis.. What is the standard form of the equation for this line? 2x – 5y = –15 2x – 5y = –17 2x + 5y = –15 2x + 5y = –17
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The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y plus...
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