As the result of experimental work, a student finds the density of a liquid to be 0.1369 g/㎤. The known density of that liquid is 0.1478 g/㎤. What is the percent error of this student's work? (Round final answer to the nearest tenth if necessary

Percent error is

Step-by-step explanation:

Given:

As per the result of experimental work, density of a liquid is 0.1369 g/㎤

Known density of the liquid is 0.1478 g/㎤

To find: percent error

Solution:

The density of a substance is defined as mass per unit volume.

S.I. unit is Kilogram per cubic metre.

Error = Actual density - density as per the experiment =

Percent error = ( error/Actual error ) × 100 =

what? that isnt a question

step-by-step explanation:

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb