Use long division to find the quotient below. (12x3 + 3x2 - 108) = (3x-6)
O A. 4x2 + 6x + 18
O B. 4x2 + 9x + 18
O C. 4x2 - 6x + 18
D. 4x2-9x+18

B

Step-by-step explanation:

12x^3+3x^2-108 = 3x-6

3(4x^3+x^2-36) =3(x-2) ( divide by 3 both sides)

4x^3+x^2-36=x-2

4x^3+x^2-36

4x^3+x^2-36/x-2 =

divisor  4x^2           :(4x^2) (x-2) =4x^3-8x^2

                                 4x^3+x^2-36-4x^-8x^2 =9x^2-36

then divisor is 9x  :      9x(x-2)= 9x^2-18x

the remainder is :          9x^2-18x-9x^2-36 = 18x-36

then divisor is  18:              18(x-2) = 18x-36

subtract : 18x-36-(18x-36)= 0

the answer is 4x^2+9x+18

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.