A container has 14 yellow chips, 10 blue chips, and 12 red chips in it. One chip is randomly chosen from the container, then a second chip is randomly chosen after replacing the first chip. What is the probability that both chips are red? IN SIMPLEST FORM

1/9

Step-by-step explanation:

So, we are given the following data or parameters or infomation in the question above;

=>" A container has 14 yellow chips, 10 blue chips, and 12 red chips in it. "

=> "One chip is randomly chosen from the container, then a second chip is randomly chosen after replacing the first chip."

Therefore, the total number of chips in the container = 14 + 10 + 12 = 36 chips.

The probability of drawing a red chip in the first draw = 12/36 = 1/3.

The probability of drawing a red chip in the second draw = 1/3 also.

Thus, the probability that both chips are red => 1/3 × 1/3 = 1/9.

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

chicken chicken chicken

step-by-step explanation: