How would you solve this? All I know is AD=24.4948

8

Step-by-step explanation:

Let's call the center of the middle circle J, and the center of the third circle K.

Draw a line from J to the line AD such that the line is perpendicular to AD.

This forms a right triangle that is similar to the triangle ΔADK.

Writing and solving a proportion:

x / DK = AJ / AK

x / 5 = 15 / 25

x = 3

Now, draw lines from J to B and C.  We now form two congruent right triangles, where the hypotenuse is 5 and the shared leg is 3.

That means these are both 3-4-5 triangles.

Therefore, BC = 4 + 4 = 8.

6 on both sides and twelve on the top and the bottom

step-by-step explanation: