A man is one year older than twice the age of his son. The sum of their ages is 100. How old are they?

Undo the equation

Y x 3 + 1 = 100

Y = Age of Son

Undo by doing inverse operations

Subtract 1 and divide by 3

100-1=99

99/3=33

33 is younger son's age

33 x 2 = 66 + 1 = 67

Younger son's age is 33 and man is 67

Hope this helps. If you have any questions you may ask

Step-by-step explanation:

in the attachment.   i didn't see your choices.   the word which means there is choices.

step-by-step explanation:

(x,y)

x tells you how much left or right you go from the origin

y tells you how much down or up you go from the origin

so for example (-3,2), you go left 3 and up twice. i denoted which of the ordered pairs is which in my graph.

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation: