If a+b+c=16 and a^2+b^2+c^2=90 then find the value a^3+b^3+c^3-3abc

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

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