Jane is using a sextant to measure her distance from a building of height 270 feet. Her eyes are 5 feet 3 inches above the ground. The angle of elevation from her viewpoint using the
sextant is 40°. How far away, measured to the nearest foot, is Jane from the building?
a) 221 feet b) 203 feet c) 170 feet d) 316 feet e) none of these.

d) 316 feet

Step-by-step explanation:

Now 3 Inches = 0.25 feet

Therefore:  5 feet 3 inches =5.25 feet

The problem forms a right triangle in which the height of the triangle

= 270 -5.25  =264.75 feet.

Using Trigonometric ratios

Therefore, Jane is approximately 316 feet from the building.

d) 316 feet

Step-by-step explanation:

A right angled triangle ABC is formed.

BC represents the height of the building minus the height of Jane's eyes from the ground. AB represents Jane's distance from the building.

12 inches = 1 feet

3 inches = 3/12 = 0.25 feet

Therefore, the height of her eyes from the ground is 5 + 0.25 = 5.25 feet

Therefore, BC = 270 - 5.25 = 264.75 feet

To determine AB, we would apply the the tan trigonometric ratio which is expressed as

Tan# = opposite side/adjacent side

Tan 40 = 264.75/AB

AB = 264.75/tan40

AB = 264.75/0.839

AB = 316 feet

if im undersanding the question correctly, its organized from 10

step-by-step explanation:

move it to the other side

step-by-step explanation: