TEN POINTS AVAILABLE: Suppose f(x) = ax^2 +bx+ c is the equation of a parabola. Explain how f(4) = 1 relates to the graph. a. (4, 1) is the vertex of the parabola
b. (1, 4) is the vertex of the parabola
c. (4, 1) is a point on the parabola
d. (1, 4) is a point on the parabola

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

answer: y=0 if that is what u r looking for

answer: 8d

step-by-step explanation:

45+5= 50+5=55+5=60