A rectangular field measures 616m by 456m. Fencing posts are placed along it's sides at equal distances. What will be the distance between the posts if they are place as far apart as possible?

766.41m

Step-by-step explanation:

Hi, since the situation forms 2 right triangles (see attachment) we have to apply the Pythagorean Theorem for one triangle.  

c^2 = a^2 + b^2  

Where c is the hypotenuse of the triangle (in this case the diagonal distance between corners of the field, which is the distance between the posts if they are placed as far apart as possible ) and a and b are the other sides.  

Replacing with the values given:  

c^2 = 616^2 + 456^2  

c^2 = 379,456+207,936  

c^2 =587,392

c = √587,392

c = 766.41m

So, she is within the area serviced by the tower (20 miles)  

Feel free to ask for more if needed or if you did not understand something.  

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

19.side- angle- side

20. angle- side- angle

step-by-step explanation: