13) The table below shows a list of students in math
classes based on their
grade and class. If you
pick a student at random,
what is the probability
they are in Algebra 2 given
that they are a 10th
grader?

60/257 or .233

Step-by-step explanation:

P (algebra 2 | 10th grade) = # algebra 2 in 10th grade / # 10th graders

Total number of 10th graders = 85 + 100 + 60 + 10 + 2 = 257

Algebra 2 students in 10th grade = 60 (look at the intersection of the 10th  grade column and the algebra 2 row)

P (algebra 2 | 10th grade) = 60/257

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

36 girls

step-by-step explanation:

the 48 boys is 4 parts of the ratio

divide 48 by 4 to obtain one part of the ratio

= 12 ← 1 part of the ratio

3 parts = 3 × 12 = 36 ← number of girls