Determine the center and radius of the following circle equation: x2 + y2 + 10x + 20y + 109 = 0
Center:
Radius:
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problem 1 out of max

The equation of the circle  (x + 5 )² + ( y + 10 )² = (4)²

Center of the circle ( h, k) = ( -5 , -10)

Radius of the circle     ' r' = 4

Step-by-step explanation:

Explanation:-

Given circle equation is x² + y² +10 x + 20 y +109 =0

                                     x² +10 x +  y² + 20 y +109 =0

  x² +2 (5) (x)+(5)² -(5)²+ y² +2(10) y + (10)²-(10)² +109 =0

By using formula

(a+b)² = a² + 2 a b + b²

(x + 5 )² + ( y + 10 )² - 25 - 100 + 109 = 0

(x + 5 )² + ( y + 10 )² - 16 = 0

(x + 5 )² + ( y + 10 )² = 16

(x + 5 )² + ( y + 10 )² = (4)²

The standard equation of the circle  ( x - h )² + ( y -k)² = r²

Center of the circle ( h, k) = ( -5 , -10)

Radius of the circle     ' r' = 4

Conclusion:-

The equation of the circle  (x + 5 )² + ( y + 10 )² = (4)²

Center of the circle ( h, k) = ( -5 , -10)

Radius of the circle     ' r' = 4

idk

step-by-step explanation:

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.