On a multiple-choice test, each question has 4 possible answers. A student does not know answers to three questions, so the student guesses.

What is the probability that the student gets all three questions wrong?

42.1875% probability that the student gets all three questions wrong

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the student gets it wrong, or he does not. The probability of the student getting a question wrong is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probabily distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.

On a multiple-choice test, each question has 4 possible answers.

One of these options is correct and the other 3 are wrong. We want to find the probability of getting questions wrong. So

Three question:

This means that

What is the probability that the student gets all three questions wrong?

This is P(X = 3).

42.1875% probability that the student gets all three questions wrong

one that is bigger than 3 1/2

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.