We are going to fence in a rectangular field that encloses 200m2. If the cost of thematerial for of one pair of parallel sides is $3 per meter and cost of the material for theother pair of parallel sides is $8 per meter determine the dimensions of the field thatwill minimize the cost to build the fence around the field.

Step-by-step explanation:

Let be x and y the length and width of the rectangular field, whose area and perimeter are, respectively:

Building cost is minimum when perimeter is minimum, then equation system must be reduced and critical values have to be found:

Then,

Now, critical values are determined by First and Second Derivative Tests:

FDT

(As length is a positive number)

SDT

(which means that critical point leads to a minimum).

Now, the value of the other variable is:

Lastly, the cost of building the fence is:

30

step-by-step explanation:

times by times

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x