Using the equation y−1=2(x+3) , find a point that is on the line when graphed. (−1,3)
(−3,1)
(1,−3)
(3,1)

(- 3, 1 )

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

y - 1 = 2(x + 3) ← is in point- slope form

with (a, b) = (- 3, 1 )

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )