1. In triangle ABC, if AB = 3cm, BC = 4cm and AC = 5cm Find A. The area of triangle ABC
B. The length of shortest altitude
What is the length of its diagonal

Step-by-step explanation:

A) The diagram of the triangle is shown in the attached photo

The lengths of the given triangle form a Pythagoras triple. This means that the square of the longest side equals the sum of the squares of the two shorter sides.

Area = 1/2 × base × height

Height = 3 cm

Base = 4 cm

Area = 1/2 × 3 × 4 = 6 cm²

B) The altitudes can be AB or BC. Therefore, the length of the shortest altitude is AB = 3 cm

The diagonal is the same as the hypotenuse which is also the longest side of the triangle. Thus,

Length of diagonal = 5 cm

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation: