plss help asap Around which line would the following cross-section need to be revolved to create a sphere? circle on a coordinate plane with center at 1 on the x-axis and a radius of 1 y = x y-axis x = 1 y = 1

The correct option is;

x = 1

Step-by-step explanation:

The parameters given are;

Location of circle center = 1 on the x axis

Radius of circle = 1

Required operation on circle = Revolving to create a sphere

To form a spherical shape by the rotation of a circular figure involves rotating the circular figure about a line passing through the center of the circle

Therefore, to form a sphere, the circle should be about a line that passes through x = 1

Hence, the circle should be rotated about the line x = 1.

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3