m∠AOC m, angle, A, O, C is a straight angle. m∠AOB=8x+51∘\qquad m \angle AOB = 8x + 51^\circ m∠AOB=8x+51 ∘ m, angle, A, O, B, equals, 8, x, plus, 51, degrees m∠BOC=6x−25∘\qquad m \angle BOC = 6x - 25^\circ m∠BOC=6x−25 ∘ m, angle, B, O, C, equals, 6, x, minus, 25, degrees Find m∠AOBm\angle AOB m∠AOB m, angle, A, O, B :

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.