∆ABC is reflected across the x-axis, then rotated 90° clockwise about the origin, and finally reflected across the line y = x to form ∆A′B′C′. The coordinates of vertex A′ are . The coordinates of vertex B′ are . The coordinates of vertex C′ are .

Step-by-step explanation:

Notice that the vertices are A(1,1), B(2,3) and C(2,1).

A reflection across the x-axis give the coordinates A'(1,-1), B'(2,-3) and C'(2,-1). Then, we apply the rotation 90° clockwise about the origin A'(1,1), B'(3, 2) and C'(1, 2).

Finally, a reflection across the line y = x, gives A'(1,1), B'(2,3) and C'(2,1)

Therefore, the coordinates of the image are A'(1,1), B'(2,3) and C'(2,1).

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

5

step-by-step explanation: