Consider the enlargement of the rectangle. A smaller rectangle with length of x inches and width of three-fifths inch. A larger rectangle with length of 20 inches and width of 12 inches. What is the correct multiplication of a cross product to solve for the missing dimension?

The new rectangle is 20 times larger than the original rectangle.

So multiply both length and width of smaller rectangle with 20 to get larger rectangle

x=1

Step-by-step explanation:

Lenght of smalled rectangle = x

Width of smaller rectangle = 3/5 inches

Lenght of larger rectangle = 20

Width of larger rectangle = 12

Find the ratio of width of large rectangle to small rectangle: : 20

Divide length of larger rectangle with 20 to find x:  

the revenue of the fitness center, y, is the product of two factors: the number of members and the fee paid by each member. there are 320 members now, but number of members goes down by 10 for each $5 increase in fees, so if x is the number of $5 price increases then members is equal to (320 - 10x). since the fee is currently $45, and the fee increases by $5 for every price bump x, the fee is given by (45 + 5x). so, revenue y is given by y = (320 - 10x)(45 + 5x).