Solve cos x + sqrt2 = -cos x for x over the interval [0,2pie] A. x= 3pie/4
B. x= 3pie/4 + 2npie
C. x= 3pie/4 and 5pie/4
D. x= pie/4 and 7pie/4

sine

step-by-step explanation:

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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