Triangle ABC with vertices A(-4,-3), B(4,-4), and C(5,5) is translated by (x, y) → (x-7.y + 6). Then the image, triangle A'B'C', is translated by (x, y) → (*+9,7 – 2), resulting in A"B"C".
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Find the coordinates for the vertices of triangle A "B"C".
The coordinates are A"
Enter a rule for one translation that maps triangle ABC to triangle A "B"C".
A single rule that maps triangle ABC to triangle A " "C"'is (,Y) – (*+
Y +

b

step-by-step explanation:

given

- 2 (3x + 12y - 5 - 17x - 16y + 4 )

simplify the parenthesis by collecting like terms

= - 2 (- 14x - 4y - 1) ← distribute the parenthesis by - 2

= 28x + 8y + 2 → b

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

the answer is a

step-by-step explanation: