On a coordinate plane, a triangle has points R (negative 1, 3), S (3, negative 2), and T (1, negative 4). Which reflection will produce an image of ΔRST with a vertex at (2, –3)? a reflection of ΔRST across the x-axis a reflection of ΔRST across the y-axis a reflection of ΔRST across the line y = x a reflection of ΔRST across the line y = –x

a reflection of ΔRST across the line y = –x

Step-by-step explanation:

A reflection across the line y = –x transforms point (x, y) into (-y, -x)

After reflecting ΔRST across the line y = –x we get:

R (-1, 3) -> (-3, 1)

S (3,-2) -> (2, -3)

T (1, -4) -> (4, -1)

where S is at the desired vertex

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

the answer is d

the answer is in the first quadrant, which make the y-int positive.

since the dots are going down, therefore the correlation is negative

i hope it is right.