6. Mr Chua's car consumes petrol at an average rate of 8 litres daily. Before Mr Chua begins his journey,

he tops up the petrol in his car to 100 litres. Given

that he will next top up the petrol in his car when

there are 20 litres left, form an inequality and solve

it to find the maximum number of days he can travel

before he has to top up the petrol in his car. 10

He can travel up to 9 days before he has to top up the petrol in his car.

Step-by-step explanation:

Hi, to answer this question we have to write an inequality with the information given:

The petrol available (100) minus the amount that his car consumes per day (8x) must be higher to 20 (liters left)

Mathematically speaking:

100- 8x > 20

Where x is the number of days.

Solving for x:

100-20>8x

80 > 8x

80/8> x

10>x

x <10

x must be less than 10 days .

He can travel up to 9 days before he has to top up the petrol in his car.

7.25

step-by-step explanation:

we know that 7 equals to 7.0. we also know that 1/4=0.25. so we can add the two together and we get 7.25

168

step-by-step explanation:

first off, we know that he drove 3.5 hours at a rate of 48 mph.

knowing that, we want to see how many miles he drove all-together.

in this case, we can just multiply 48 by 3.5.

48 * 3.5 = 168