A random sample of 1,000 StatCrunchU students contains 598 female and 402 males. We analyze responses to the question, "What is the total amount (in dollars) of your student loans to date?" Two sample T confidence interval: μ 1: Mean of Loans where Gender="Female" μ 2: Mean of Loans where Gender="Male" μ 1 − μ 2: Difference between two means (without pooled variances) 95% confidence interval results: Difference Sample Diff. Std. Err. DF L. Limit U. Limit μ 1 − μ 2 516.74334 368.41116 907.34739 -206.29374 1239.7804 What can we conclude from the 95% confidence interval? Check all that apply. Group of answer choices

We are 95% confident that at StatCrunchU female students carry anywhere from $206.29 to $1239.78 more in students loan debt than male students.

We are 95% confident that the mean gender difference in student loan debt in the sample is $516.74.

Step-by-step explanation:

The StatCrunchU students sample has 598 female and 402 males. The 95% confidence interval enable us to determine that the female students carry more loan debt than males. The female students carry from $206.29 to $1239.78 more loan debt than the male students. The mean limit μ 1 − μ 2 determines the difference of gender among the students loan debt.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

is there answer choices?