A sample consists of 80 separate events that are equally likely what is the probability of each?

Step-by-step explanation:

This problem brothers is the probability of mutually exclusive events,

Given the sample space of 80 separate events, the probability of of one event happening is

Pr(each event)=

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116