Suppose that a particular experiment will have outcome "A" with probability 13 and outcome "B" with probability of 23. If you were to perform this experiment 90 times, approximately how many times would you expect outcome "B" to occur.

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

c

step-by-step explanation: