250cm3 of fresh water of density 1000kgm-3 is mixed with 100cm3 of sea water of density 1030kgm-3. Calculate the density of the mixture. *

And we can do a similar procedure for the sea water:

And after convert the volume to m^3 we got:

And then the density for the mixture would be given by:

And replacing we got:

Step-by-step explanation:

For this case we can begin calculating the mass for each type of water:

And after convert the volume to m^3 we got:

And we can do a similar procedure for the sea water:

And after convert the volume to m^3 we got:

And then the density for the mixture would be given by:

And replacing we got:

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

its 50 miles away from the starting point