AD←→ is tangent to circle M at point D. The measure of ∠DMQ is 58º. What is the measure of ∠DQM ?

32°

Step-by-step explanation:

Given:

∠DMQ = 58º

In this circle, the radius is DM. Since AD is tangent to the circle M, at point D, and the angle between a tangent and a radius is 90°

Therefore, ∠MDQ = 90°

The total angle in a triangle is 180°. Since we have the values of ∠MDQ and ∠DMQ, ∠DQM will be calculated as:

180 = ∠DMQ + ∠MDQ + ∠DQM

Solving for ∠DQM, we have:

∠DQM = 180 - ∠DMQ - ∠MDQ

∠DQM = 180 - 90 - 58

∠DQM = 32°

The measure of ∠DQM is 32°

idk

step-by-step explanation:

do it yourself, cause that made me do it myself today, in english!