Simplify (x^4y)^3.
x^12y^3
x^4y^3
x^7y^3

Explanation:

Think of x^4y as x^4y^1. When we raise this to the third power, we multiply the outer exponent 3 by each inner exponent

x^4 turns into x^12

y^1 turns into y^3

This is one way to show your work

(x^4y)^3

(x^4y^1)^3

x^(4*3)*y^(1*3) ... multiplying outer exponent by each inner exponent

x^12y^3

A more lengthy way to get the answer is to write x^4y out three times multiplying by itself that many times. The outer exponent 3 tells us we will have three copies of x^4y multiplied with itself.

(x^4y)^3 = (x^4y)*(x^4y)*(x^4y)

(x^4y)^3 = (x^4*x^4*x^4)*(y*y*y)

(x^4y)^3 = ( x^(4+4+4) ) * ( y^(1+1+1) )

(x^4y)^3 = x^12y^3

answer: for each 3 girls there is 2 boys . 3: 2

hope this ! (:   mark me as brainliest if you can

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,