The net of a solid is shown below: Net of a square pyramid showing 4 triangles and the square base. The square base has side lengths of 3 inches. The height of each triangle attached to the square is 4 inches. The base of the triangle is the side of the square. What is the surface area of the solid? WILL GET BRANLIEST! <3

33 sq in

Step-by-step explanation:

Area of each triangular face is 1/2×3×4 = 6sq in

Hence total area of four(4) faces is 6×4 = 24sq in

Area of base is 3×3 = 9sq in

Hence Total area of pyramid is 24+9 = 33sq in

3. parallelogram

step-by-step explanation:

we turn each of our sides into direction vectors

ab=b-a=(3 - 7, 1 - 0) = (-4, 1)

bc=c-b=(1,6)

cd=d-c=(4,-1)

da=a-d=(-1,-6)

we see how the opposite sides have negated direction vectors; this is characteristic of a parallelogram.   we have congruent sides ab=cd and bc=da with unequal lengths because 1^2+6^2 is different from (-4)^2+1^2.   so it's not a square or a rhombus.  

we check the dot product of direction vectors of adjacent sides.   we have

ab dot bc = -4(1) + 1(6) = 2

that's not zero so the sides are not perpendicular.   we've ruled out rectangle.

the direction vectors indicate two pairs of congruent parallel sides, so we choose parallelogram over trapezoid.

i need the options

step-by-step explanation: