£2200 is deposited in a bank paying 0.5% simple interest per annum. How much interest will have been paid after 18 years?

The answer would be £198

principal (p) = 2200

Rate (R) = 0.5%

Time (T) = 18

Interest(I) = ?

Now,

or, Interest. = P×T×R/100

or, Interest = 2200×18×0.5/100

or, Interest = 19800/100

Hence, Interest = 198

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph

a c

step-by-step explanation: