Suppose that in circle with center P, and a central angle, ∠OPQ, intersects minor arc OQ, where the measure of arc OQ = 82◦, and the measure of ∠OPQ is (5x – 3) ◦. What is the value of x?

Central Angle OPQ = Arc OQ = 82°

5x - 3 = 82°

5x = 85°

x = 17 degrees

Step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

total of apples - take away four

6-4 = 2

answer is 2 apples