Determining Linear Inequalities with No Solution Which linear equality will not have a shared solution
set with the graphed linear inequality?
5
8
Oy> 2 x + 2
y2-2
3
4
O y<-x-7
y> -+-5
y -8
-4
4
8
-4
-8

Does the function satisfy the hypotheses of the mean value theorem on the given interval? f(x) = 4x^2 + 3x + 4, [−1, 1] no, f is continuous on [−1, 1] but not differentiable on (−1, 1). no, f is not continuous on [−1, 1]. yes, f is continuous on [−1, 1] and differentiable on (−1, 1) since polynomials are continuous and differentiable on . there is not enough information to verify if this function satisfies the mean value theorem. yes, it does not matter if f is continuous or differentiable; every function satisfies the mean value theorem.