Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), and G (6, 1). He has 16 units of fencing. Where could Alex place point H so that he does not have to buy more fencing? (0,1)
(0,-2)
(1,1)
(1,-2)

H: (1,1)

Step-by-step explanation:

Find Distance EF

D=sqrt((5-5)^2+(3-1)^2)

D=sqrt(4)

D=2

Find distance FG

D= sqrt((5-1)^2+(3-6)^2)

D= sqrt(4^2+(-3)^2)

D= sqrt(16+9)

D= sqrt (25)

D=5

Find distance From G to (1,1)

D= sqrt((1-1)^2+(1-6)^2)

D=sqrt(0^2+(-5)^2)

D=sqrt(25)

D=5

Find distance from (1,1) to E

D= sqrt((1-5)^2+(1-1)^2)

D= sqrt((-4)^2+0^2)

D= sqrt(16)

D= 4

P=2+5+5+4=16

g

step-by-step explanation:

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

happy to

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