Hosn is a picture framer. He is framing a picture that is 24 inches by 32 inches with a frame that is 2.5 inches wide. What is the outer perimeter of the framed picture In yards, feet, and inches.

Perimeter is the sum of the side lengths of a shape. The outer perimeter of the framed picture is:

Given that:

The width of the frame is given as:

So, the actual length and width of the framed picture is:

The outer perimeter (P) in inches is:

So, we have:

The perimeter in yard, is as follows:

The perimeter in feet is as follows:

Hence, the outer perimeter of the frame is 132 inches

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122 sq. in.

Step-by-step explanation:

P = 2 (l + w)

P = 2 (34.5 + 26.5)

P = 2 x 61

P = 122 sq. in. = 0.847 sq ft = 0.0941 sq. yards

24

step-by-step explanation: