Triangle ABC has vertices at A(-4, -2), B(1, 7) and C(8, -2) A) Determine the exact value of the area of Triangle ABC.

B) Determine the perimeter of Triangle ABC to the nearest tenth.

a). Area = 54 square units

b). Perimeter = 33.7 units

Step-by-step explanation:

Vertices of the triangle ABC are A(-4, -2), B(1, 7) and C(8, -2).

(a). Area of the triangle ABC = (Absolute value)

By substituting the values from the given vertices,

Area =

        =

        =

        = (-54) unit²

Therefore, absolute value of the area = 54 square units

(b). Distance between two vertices (a, b) and (c, d)

        d =

     AB =

           =

           = 10.295 units

     BC =

           =

           = 11.402 units

     AC =

           = 12 units

     Perimeter of the triangle = AB + BC + AC = 10.295 + 11.402 + 12

                                                                          = 33.697

                                                                          ≈ 33.7 units

f

step-by-step explanation:

f

25% is the answer